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 Library > Diseases and Medications > The Medicine Cabinet > Use of PP to Control External Infections of Ornamental Fish |
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Use of Potassium Permanganate to Control External Infections of Ornamental Fish | |
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Page 3 of 5 | Pages: 1 . 2 . 3 . 4 . 5 | |
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Treatment Failure Poor efficacy following use of potassium permanganate is usually caused by one of three factors: (1) incorrect or incomplete diagnosis; (2) incorrect calculation or measurement of amount of chemical needed; and (3) excessive organic material in the system resulting in rapid degradation of the chemical. Any time treatment failure occurs, sick fish should be submitted to a diagnostic laboratory for an accurate diagnosis. Volume of the water treated, accuracy of calculations to determine treatment rate, and accurate measurement (by weight) of chemical used are essential for delivery of an appropriate chemical dose. As mentioned above, an excessive amount of organic matter in the system will result in rapid deactivation of potassium permanganate, and therefore contact time with active chemical will be inadequate for effective treatment. This is often a problem in heavily stocked ponds. Determining the Amount of Potassium Permanganate to Use To calculate the amount of chemical required, a simple formula can be used: Amount of Chemical = Volume x Conversion Factor x Treatment Rate If the pond or tank volume is measured in gallons, the conversion factor is 0.0038 and the answer will be given in grams (see Table 1 for other conversion factors). For a treatment rate of 2 mg/L, this formula would be: Grams of Chemical = Gallons Treated x 0.0038 x 2 mg/L Therefore, to treat a 250-gallon vat, the grams of potassium permanganate needed are: Grams needed = (250 gal) x (0.0038) x (2 mg/L) = 1.9 grams An inexpensive gram scale can be obtained by purchasing a dietary scale at your local grocery store or pharmacy. One level teaspoon of potassium permanganate weighs about 7.0 grams. more ... |
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